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Question

Construct a ΔPQR, in which PQ=6cm, QR=7cm and PR=8cm. Then construct another triangle whose sides are 45 times the corresponding sides of ΔPQR

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Solution

Steps of construction :

1. Draw a line segment PQ=6 cm

2. Draw an arc, using P as a centre and radius 8 cm

3. Draw another arc, using Q as a centre and radius 7 cm

4. Now, join PR and QR to get ΔPQR

5. Draw a ray PX by making an acute angle, angle QPX

6. Divide PX into 4 equal parts.
P1,P2,P3,P4,P5 such PP1=P1P2=P2P3=P3P4=P4P5

7. Join P5Q

8. Draw a line P4Q which is parallel to QR

9. Similar to step 8, draw a line QR which is parallel to QR.
Therefore, ΔPQR is the required triangle.

1537982_1713723_ans_b79c4ed3c49b4e04976b003b99e21eb8.png

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