Construct a frequency table with equal class intervals from the following data on the daily wages (in Rs.) of 28 labourers workiing in a factory, taking one of the class intervals as 210-230 (230 not included) .
220, 268, 258, 242, 210, 268, 272, 242, 311, 290, 300, 320, 319, 302,318, 306, 292, 254, 278, 210, 240, 280, 316, 306, 215, 256, 236.

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Solution

Sol:

Minimum observation is 210 and maximum observation = 320

So the range is (320-210) =110

The classes of equal size covering the given data are:

(210-230), (230-250), (250-270), (270-290), (290-310), (310-330)

Thus the frequency distribution may be given as:

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Similar questions

Construct a frequency table with equal class intervals froin the following data on the monthly wages (in rupees) of 28 labourers working in a factory, taking one of the class intervals as 210-230 (230 not included): 220, 268, 258, 242, 210, 268, 272, 242, 311, 290, 300, 320, 319, 304, 302, 318, 306, 292, 254, 278, 210, 240, 280, 316, 306, 215, 256, 236.

A grouped frequency table with class intervals of equal sizes using 250 – 270 (270 not included in this interval) as one of the class intervals is constructed for the following data.

268, 220, 368, 258, 242, 310, 272, 342

310, 290, 300, 320, 319, 304, 402, 318

406, 292, 354, 278, 210, 240, 330, 316,
406, 215, 258, 236.

The frequency of class 310 - 330 is:

Question 8
A grouped frequency table with class intervals of equal sizes using 250 – 270 (270 not included in this interval) as one of the class intervals is constructed for the following data.

268, 220, 368, 258, 242, 310, 272, 342

310, 290, 300, 320, 319, 304, 402, 318

406, 292, 354, 278, 210, 240, 330, 316,
406, 215, 258, 236.

The frequency of class 310 - 330 is:

A) 4
B) 5
C) 6
D) 7

Q. The weekly wages (in rupees) of 28 workers of a factory are given below:
668, 610, 642, 658, 668, 620, 719, 720, 700, 690, 710, 642, 672, 654, 692, 706, 718, 702, 704, 678, 615, 640, 680, 716, 705, 615, 636, 656.
Construct a frequency table with equal class intervals, taking the first of the class intervals as 610−630, where 630 is not included.

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Sol: Minimum observation is 210 and maximum observation = 320 So the range is (320-210) =110 The classes of equal size covering the given data are: (210-230), (230-250), (250-270), (270-290), (290-310), (310-330) Thus the frequency distribution may be given as:

Sol:

Minimum observation is 210 and maximum observation = 320

So the range is (320-210) =110

The classes of equal size covering the given data are:

(210-230), (230-250), (250-270), (270-290), (290-310), (310-330)

Thus the frequency distribution may be given as: