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Question

Construct a histogram from the following distribution of total marks obtained by 65 students of X class in the final examination

Marks(midpoints):150160170180190200No. of students810251273


A

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B

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C

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D

None of these

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Solution

The correct option is C


Ascertainment of lower and upper class limits:

Since the difference between the second and first mid – point is 160 -150 =10

h=10h2=5

So, lower and upper limits of the first class are 150 -5 and 150 + 5 i.e. 145 and 155 respectively

First class interval is 145 – 155

Using the same procedure, we get the classes of other mid-points as under:

Marks:145155155165165175175185185195195205No. of students810251273

The histogram of the above frequency distribution is given in the figure.


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