Construct a quadrilateral ABCD given that AB=8 cm, BC= 8 cm, CD=10 cm, AD=10 cm and $∠ A = 45^{\circ}$

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Solution

(i) Draw a line segment AB=8 cm.

(ii) At A draw a ray AX making an angle of $45^{\circ}$ and cut off BC=8 cm.
(iii) With centre A and C radius 10 cm draw arcs interesect each other at D.
(iv) Join AD and CD.
Then ABCD is the required quadrilateral.

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