Question

Construct a quadrilateral $ABCD$ in which $AB=3.5cm,BC=3.8cm,CD=DA=4.5cm$ and Diagonal $BD=5.6cm$.

Answer 1

The given Quadrilateral $ABCD$ can be drawn by following the steps.
Step 1: Draw a line $BD=5.6cm$
Step 2: with $B$ as the centre draw an arc of $3.5cm$
Step 3: with $4.5cm$ as radius cut the arc drawn in step 2 and that point of intersection is $A$. join $BA$ and $DA$
Step 4: Draw another arc from $B$ with $3.8cm$ radius on opposite side of $BD$.
Step 5: From $D$ take $4.5cm$ as radius and cut the arc drawn in step 4 and the point of intersection is $C$. now join $BC$ and $CD$.
$\therefore$ The constructed quadrilateral looks like: