Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, ∠P = $$60\cdot$$ ∠Q = $$90\cdot$$ and ∠R = $$120^\cdot$$
Steps of Construction:
(i) Construct a line segment QR = 6 cm.
(ii) At the point Q, construct a ray QX making an angle of $$90^\cdot$$ and cut off QP = 4 cm.
(iii) At the point P, construct a ray making an angle of $$60^\cdot$$ and at R, a ray making an angle $$120^\cdot$$ which meets each other at the point S.
Therefore, PQRS is the required quadrilateral.