Question

Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, ∠P = $60\cdot$ ∠Q = $90\cdot$ and ∠R = ${120}^{\cdot }$

Answer 1

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of ${90}^{\cdot }$ and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of ${60}^{\cdot }$ and at R, a ray making an angle ${120}^{\cdot }$ which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.