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Question

Construct a quadrilateral PQRS where PQ = 4 cm, QR = 6 cm, ∠P = $$60\cdot$$ ∠Q = $$90\cdot$$ and ∠R = $$120^\cdot$$


Solution

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of $$90^\cdot$$ and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of $$60^\cdot$$ and at R, a ray making an angle $$120^\cdot$$ which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.


1712165_1809572_ans_29772ce6354a4834ae1473e1a6222ff5.PNG

Mathematics

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