Construct a rectangle $A B C D$ given
$A B = 6 c m, B C = 5 c m$

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Solution

We know that in rectangle measure of each angle is $90^{o}$ and opposite sides are equal.
$\Rightarrow$ Draw a line segment $A B = 6 c m$ .
$\Rightarrow$ Construct angle of $90^{o}$ at points $A$ and $B$
$\Rightarrow$ Cut off $A D = 5 c m$ and $B C = 5 c m$
$\Rightarrow$ Join $C D$ .

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A B C D

A B = 4 c m

B C = 6 c m

Construct a rectangle ABCD whose one side BC = 4.5 cm and diagonal AC = 6 cm [3 MARKS]

A B C D

A B = 5 c m, B C = 6 c m, C D = 4 c m, A D = 3 c m

A C = 5 c m .

A B C

A B = 6 c m, B C = 5 c m

C A = 5 c m

Construct a quadrliateral ABCD; if:

(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and $∠$ ABC = $75^{\circ}$ .

(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and $∠ BCD = 60^{\circ}$

(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, $∠ A = 60^{\circ}$ and $∠ B = 75^{\circ}$ .

(iv) AB = 5 cm, BC = 6.5 cm, CD = 4.8 cm, $∠ B = 75^{\circ}$ and $∠ C = 120^{\circ}$

(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.

(vi) AB = AD = 5 cm, BD = 7 cm and BC = DC = 5.5 cm

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