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Question

Construct a rhombus ABCD where AC=6 cm and BD=7 cm. O is the intersection of the diagonals. Then the length of OC+OB is :

A
7 cm
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B
6 cm
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C
6.5 cm
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D
8 cm
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Solution

The correct option is C 6.5 cm
1. Draw a diagonal AC=6 cm.
2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O ( Diagonals of rhombus intersects at right angle)
3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D
4. Join AB,AD,BC,CD.
5. ABCD is the required rhombus.
6. OC+OB=3+3.5=6.5 cm

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