Construct a right-angled triangle $P Q R$ in which $Q R = 4.5 c m$ and hypotenuse $P R = 6 c m$ .

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Solution

Steps
i) Draw $Q R = 4.5 ㎝$
ii) From point Q, draw a perpendicular to QR
iii) From R, taking a radius of $6 ㎝$ , cut an arc.
iv) Point of intersection of perpendicular line and the arc is P. Join PQ and PR

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Construct a right angled triangle PQR, in which $∠ Q = 90^{o}$ ,hypotenuse PR=8 cm and QR=4.5 cm. Draw bisector of angle PQR and let it meet PR at point T. Prove that T is equidistant from PQ and QR.

Q. Construct a right angled

△ P Q R

, in which

∠ Q = 90^{\circ}

, hypotenuse

P R = 8

cm and

Q R = 4.5

cm.

Q. Construct a right angled triangle

X Y Z

with

X Y = 4.5 c m

and hypotenuse

Y Z = 6 c m

Q. Construct a right angle

△ P Q R

, where

P Q = Q R

, and hypotenuse

P R = 8

units. Also, find the length of

P Q

△ P Q R

Construct right angle triangle PQR in which ∠Q = 90°, QR = 4.5 cm and ∠R = 50°.

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Construct a right-angled triangle PQR in which QR=4.5 cm and hypotenuse PR=6 cm.

Stepsi) Draw QR=4.5㎝ii) From point Q, draw a perpendicular to QRiii) From R, taking a radius of 6㎝, cut an arc.iv) Point of intersection of perpendicular line and the arc is P. Join PQ and PR

Construct a right-angled triangle $P Q R$ in which $Q R = 4.5 c m$ and hypotenuse $P R = 6 c m$ .

Steps
i) Draw $Q R = 4.5 ㎝$
ii) From point Q, draw a perpendicular to QR
iii) From R, taking a radius of $6 ㎝$ , cut an arc.
iv) Point of intersection of perpendicular line and the arc is P. Join PQ and PR