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Question

Construct a triangle ABC, with  AB=5.6 cm, AC=BC=9.2 cm.

Find the points equidistant from AB and AC; and also 2 cm from BC.

Measure the distance between the two points obtained.


Solution

Steps of Construction:

i) Draw a line segment AB = 5.6 cm

ii) From A and B, as centers and radius 9.2 cm, make two arcs which intersect each other at C.

iii) Join CA and CB.

iv) Draw two lines n and m parallel to BC at a distance of 2 cm

v) Draw the angle bisector of which intersects m and n at P and Q respectively.

P and Q are the required points which are equidistant from AB and AC.

On measuring the distance between P and Q is 4.3 cm.

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