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Question

# Construct a triangle of sides 5cm,6cm and 7cm, then construct a triangle similar to it, whose sides are 23 of corresponding sides of the first triangle.

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Solution

## Making the triangle Draw a line segment AB = 5 cm Draw an arc at 6 cm from point A. Draw an arc at 7 cm from point B so that it intersects the previous arc. Joint the point of intersection from A and B. This gives the required triangle ABC. Dividing the base: Draw a ray AX at an acute angle from AB Plot three points on AX so that; AA1 = A1A2 = A2A3 Join A3 to B. Draw a line from point A2 so that this line is parallel to A3B and intersects AB at point B' Draw a line from point B' parallel to BC so that this line intersects AC at point C' ⇒△AB′C′ is the required triangle

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