Question

Construct a triangle $PQR$ in which $PQ=5.4cm,QR=5.5cm$ and $\angle PQR={55}^{\circ }$

Answer 1

Steps of Construction:

(i) Draw a line segment which is sufficiently long using ruler.

(ii) Locate points $P$ and $Q$ on it such that $PQ=5.4cm$.

(iii) At $Q$, construct an angle ${55}^o$ using protractor.

(iv) With $Q$ as centre and radius $5.5\text{cm}$, draw an arc cutting $QS$ at $R$; join $PR$.

Thus $PQR$ is the required triangle.