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Question

Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are 112(or32) times the corresponding sides of the isosceles triangle.

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Solution

Steps of Construction:

1. Draw a line segment BC=8 cm

2. Draw a perpendicular bisector PQ of BC dividing BC at point M.

3. From QP cut off a distance MA=4 cm

4. Join AC and AB

5. Draw an arc below BC, making an acute angle, angle CBX.

6. Along BX, mark off 3 points
B1,B2,B3 such that BB1=B1B2=B2B3

7. Join B2C

8. Join B3C which is parallel to B2C and join AC which is parallel to AC

Thus, ΔABC is required triangle.

1538295_1713774_ans_fcb5e1a87ae54ab89d520dd32321e5dd.png

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