Question

Construct $∆$LMN, such that LM = 6.2 cm, MN = 4.9 cm, LN = 5.6 cm.

Answer 1

Steps of construction:
1. Draw a line segment LM = 6.2 cm.
2. With L as the centre and a radius of 5.6 cm, draw an arc.
3. With M as the centre and a radius of 4.9 cm, draw another arc cutting the previously drawn arc at point N.
4. Join LN and MN.

Thus, $∆$LMN is the required triangle.