Construct LMN such that MN = 6.2 cm, M =50 and LN LM = 2.4 cm.
Open in App
Steps of construction:
1. Draw MN = 6.2 cm.
2. Draw ray MX, such that .
3. With M as centre and radius 2.4 cm, draw an arc intersecting ray MX in point D.
4. Join D and N.
5. Draw the perpendicular bisector of seg DN, intersecting seg MX(produced) at point L.
6. Join L and N.
7. Hence, LMN is the required triangle.