Question

Construct the right angled $\Delta$ PQR, where $\angle$ Q = ${90}^{\circ }$, QR = 8 cm and PR = 10 cm.

Answer 1

To construct: A right angled triangle PQR where $\angle$ Q=${90}^{\circ }$, QR=8 cm and PQ = 10cm.
Steps of construction:


(a) Draw a line segment QR = 8cm.
(b) At point Q, draw QX perpendicular to QR.
(c) Taking R as centre, draw an arc of radius 10 cm.
(d) This arc cuts QX at point P.
(e) Join PQ.
It is the required right angled triangle PQR.