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Question

Construct the right angled $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.


Solution

To construct: A right angled  $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.
Steps of construction:
(a) Draw a line segment $$QR=8cm$$
(b) At point $$Q$$, draw $$QX\bot  QR$$
(c) Taking $$R$$ as centre, draw an arc of radius $$10cm$$
(d) This arc cuts $$QX$$ at point $$P$$
(e) Join $$PQ$$
It is the required right angled triangle $$PQR$$
1346133_1645983_ans_cbafa7974cda422fa502b6cac260eaca.png

Mathematics
NCERT
Standard VII

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