Question

# Construct the right angled $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.

Solution

## To construct: A right angled  $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.Steps of construction:(a) Draw a line segment $$QR=8cm$$(b) At point $$Q$$, draw $$QX\bot QR$$(c) Taking $$R$$ as centre, draw an arc of radius $$10cm$$(d) This arc cuts $$QX$$ at point $$P$$(e) Join $$PQ$$It is the required right angled triangle $$PQR$$MathematicsNCERTStandard VII

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