Question

Contact angle of different liquids on pure glass surface are ${\theta }_1,{\theta }_2$ and ${\theta }_3$ and their wettability are represented as $w_1,w_2$ and $w_3$ respectively. If ${\theta }_1>{\theta }_2>{\theta }_3$, then

• A. $w_1>w_2>w_3$
• B. $w_1<w_2<w_3$
• C. $w_1=w_2=w_3$
• D. None of these

Answer 1

The correct option is B $w_1<w_2<w_3$

We know,
Lower the contact angle, higher the wettability.
Given, ${\theta }_1>{\theta }_2>{\theta }_3$
$\therefore w_1<w_2<w_3$