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Question

Coordination number of Cr is six. A complex with C2O2−4, en and superoxide O−2 will be in the ratio to make complex [Cr(C2O4)x(en)y(O2)z]− :

A
x=1,y=1,z=1
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B
x=1,y=1,z=2
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C
x=1,y=2,z=2
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D
x=2,y=1,z=1
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Solution

The correct option is B x=1,y=1,z=2
As co-ordination of Cr is 6
C2O24 & en are bidentate ligands while O2 is unidentate

so x=1,y=1,z=2
[Cr(C2O4)1(en)1(O2)2]

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