Question

# Correct orders of $$I^{st}$$ I.P. are - (i) Li < B < Be < C        (ii) O < N < F (iii) Be < N < Ne(ii), (iii) (i), (ii) (i), (iii) (i), (ii), (iii)

Solution

## The correct option is D (i), (ii), (iii) Down the group ionization potential (ionization enthalpy) decreases with increase in size. Across a period, ionization potential decreases and then increases at the noble gasses.  Elements of group 2(IIA) have I.E more than that of group 13(IIA) as they have completely filled 's' orbital. Be > B Elements of group 15(VA) have more than that of group 16(VIA) as they have half filled 'P' subshell. N > O Inert gas elements have the highest I.P in a given period due to a stable electronic configuration.

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