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Question

cos1(x2+1x21)+sin1(x21x2)+tan1(x2) is equal to (where xR{0})

A
π6
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B
π4
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C
π3
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D
π2
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Solution

The correct option is B π4
x2+1x22 but x2+1x21 must be less than or equal to 1

x2=1

So cos1(1)+sin1(0)+tan1(1)

=0+0+π4=π4

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