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Question

cos 2r20.(cos x +sin x

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Solution

The given function is cos(2x) ( cosx+sinx ) 2 .

The given function can be written as,

cos(2x) ( cosx+sinx ) 2 = cos(2x) cos 2 x+ sin 2 x+2sinxcosx = cos(2x) 1+sin2x (1)

From (1), we get,

cos(2x) ( cosx+sinx ) 2 dx = cos( 2x ) 1+sin(2x) dx

Put 1+sin( 2x )=t 2cos( 2x )dx=dt

Substitute t for 1+sin(2x) and dt for 2cos( 2x )dx in (1),

cos(2x) ( cosx+sinx ) 2 dx = 1 2 1 t dt = 1 2 log| t |+c = 1 2 log| 1+sin(2x) |+c = 1 2 log| ( sin(x)+cos(x) ) 2 |+c =log( sinx+cosx )+c

Thus, the integral of the function cos(2x) ( cosx+sinx ) 2 is log( sinx+cosx )+c.


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