Cos -x cos -x- 2 x 8 - - sin -x cos-

Simplifying the L.H.S: cos( #x03C0;+x ) #x22C5;cos( #x2212;x ) sin( ...

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Trigonometric Ratios of Allied Angles

cos π+x cos -...

Question

cos (π+x) cos (-x)_ = cot2x8.(π.)sin (π-x) cos |

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\frac{cos (π + x) cos (- x)}{sin (π - x) cos [\frac{π}{2} + x]}

= {cot}^{2} x

\frac{cos (π + x) cos (- x)}{sin (π - x) cos (\frac{π}{2} + x)} = {cot}^{2} x

[cos(π+x) cos(-x)] divided by / sin(π-x) cos(π/2 + x) = cot^2x

\frac{cos (π + x) cos (- x)}{sin (π - x) cos (\frac{π}{2} + x)} = {cot}^{2} x

\frac{c o s (π + x) c o s (- x)}{s i n (π - x) c o s (\frac{π}{2} + x)} = c o t^{2} x

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