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Question

Crystal field stabilization energy for high spin $$d^4$$ octahedral complex is:


A
1.8Δ0
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B
1.6Δ0+P
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C
1.2Δ0
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D
0.6Δ0
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Solution

The correct option is D $$-0.6\Delta_0$$

For high spin $$d^4$$ Octahedral complex the splitting is given by
(Refer to Image)
$$CFSE=[-0.4\times 3+0.6\times 1]\triangle_0$$
$$=[-1.2+0.6]\triangle_0$$
$$=-0.6\triangle_0$$
$$\therefore$$ Answer is option D.


1021431_1084253_ans_1ffa0b88793b4152af2c707b1c2cfa55.png

Chemistry

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