Question

Crystal field stabilization energy for high spin $d^4$ octahedral complex is:

• A. $-1.8{\Delta }_0$
• B. $-1.6{\Delta }_0+P$
• C. $-1.2{\Delta }_0$
• D. $-0.6{\Delta }_0$

Answer 1

The correct option is D $-0.6{\Delta }_0$

For high spin $d^4$ Octahedral complex the splitting is given by

(Refer to Image)

$CFSE=[-0.4\times 3+0.6\times 1]{△}_0$

$=[-1.2+0.6]{△}_0$

$=-0.6{△}_0$

$\therefore$ Answer is option D.