D, E, F are the midpoints of the sides BC, CA and AB respectively of an equilateral $△ A B C .$ Then $△ A E F$ is congruent to triangle –

ABC

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AEF

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BFD, CDE

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AFE, BFD, CDE

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Solution

The correct options are
C
BFD, CDE

D
AFE, BFD, CDE

As the triangle is an equilateral triangle all the sides are equal.
According to mid point theorem, we get
$F E = \frac{1}{2} \times B C$
$D E = \frac{1}{2} \times A B$
$F D = \frac{1}{2} \times A C$

By the congruency axiom of SSS
$△ A E F$ is congruent to $△ F B D a n d △ E D C$

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