Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of $15 m$ , $10 m$ and $7 m$ respectively. From each can of paint $25 m^{2}$ of area is painted. How many minimum cans of paint will she need to paint the room?

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Solution

Given
Length of wall $(l) = 15 m$ ,
Breadth of wall $(b) = 10 m$
Height of wall $(h) = 7 m$

Lateral surface area of hall $= (b h + h l) = [(10) (7) + (15) (7)] = 175$

Area of ceiling $= l \times b = 15 \times 10 = 150$

Total area painted $= 175 + 150 = 325$

$1$ can of paint $= 25 m^{2}$

Total cans required $= \frac{325}{25} = 13$

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