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Question

De-Broglie wavelength of electron in second orbit of Li2+ ion will be equal to de-Broglie of wavelength of electron in:

A
n = 3 of H atom
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B
n = 4 of C5+ ion
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C
n = 6 of Be3+ ion
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D
n = 3 of He+ ion
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Solution

The correct option is D n = 4 of C5+ ion
De-Broglie wavelength is inversely proportional to velocity. When two electrons have the same velocity, they have same De-Broglie wavelength.

Velocity is directly proportional to the ratio Zn. Here Z is the atomic number and n is the number of the orbit in which electron is present.

For Li2+ ion, Zn=32.

For C5+ ion, Zn=64=32.

Since Zn is the same for both ions, they will have the same velocity and hence same De-Broglie wavelength.

Hence, the correct option is B

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