Define coefficient of mutual induction. If in the primary coil of a transformer, the current decreases from $0.8 A$ to $0.2 A$ in $4$ milliseconds, calculate the induced e.m.f in the secondary coil. Mutual inductance is $1.76 H$ .

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Solution

Coefficient of mutual induction:-
It is a measure of the induction between two circuits, It is the ratio of the electromotive force in a circuit to the corresponding change of current in neighboring circuit; usually measured in henries.
In given circuit,
$I_{1} = 0.8, I_{2} = 0.2, Δ t = 4 \times 10^{- 3}, M = 1.76$
But,
Induced emf $= V_{i n d} = M \times \frac{I_{1} - I_{2}}{Δ t}$

$∴ V_{i n d} = 1.76 \times \frac{0.8 - 0.2}{4 \times 10^{- 3}}$

$∴ V_{i n d} = 264 V$

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