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Question

Define speed. A ball is thrown up with a speed of 15 ms1. How high will it go before it begins to fall? (g=9.8 ms2)
[3 MARKS]

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Solution

Definition: 1 Mark
Problem: 2 Marks

1. Speed is defined as the total distance traveled divided by the total time it took to travel that particular distance.
2. Given, initial speed of ball, u=15 ms1
final speed of ball, v=0 (because the ball stops)
and acceleration due to gravity, g=9.8 ms2 (the ball is going up against the gravity, so the value of g is to be taken as negative).
Let the height be h.

From third equation of motion,
v2=u2+2gh
(0)2=(15)2+2×(9.8)×h
0=22519.6h
h=22519.6=225196×10=(1514)2×10=1.072×10=1.07×1.07×10=11.449

h=11.45 m

Thus, the ball will go to a maximum height of 11.45 metres before it begins to fall.


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