$Δ$ ABC is a right angled triangle. Find the length of AC. Given that BC = 3 units; AB = 4 units.

11 units

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7 units

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4 units

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5 units

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Solution

The correct option is D
5 units

In $Δ$ ABC,

$A B^{2}$ + $B C^{2}$ = $A C^{2}$ ; [By Pythagoras theorem]

$A C^{2} = 3^{2} + 4^{2}$

$A C^{2} = 25$

AC = 5 units

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ΔABC is a right angled triangle. Find the length of AC. Given that BC = 3 units; AB = 4 units.

The correct option is D 5 units In ΔABC, AB2 + BC2 = AC2; [By Pythagoras theorem] AC2=32+42 AC2=25 AC = 5 units

$Δ$ ABC is a right angled triangle. Find the length of AC. Given that BC = 3 units; AB = 4 units.

The correct option is D
5 units

In $Δ$ ABC,

$A B^{2}$ + $B C^{2}$ = $A C^{2}$ ; [By Pythagoras theorem]

$A C^{2} = 3^{2} + 4^{2}$

$A C^{2} = 25$

AC = 5 units