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Standard XII
Chemistry
Percentage Composition
Density of a ...
Question
Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is :
A
1.14
m
o
l
k
g
−
1
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B
3.28
m
o
l
k
g
−
1
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C
2.28
m
o
l
k
g
−
1
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D
0.44
m
o
l
k
g
−
1
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Solution
The correct option is
C
2.28
m
o
l
k
g
−
1
Suppose the volume of solution is 1000 ml.
1.02
g
m
of acetic acid in 1 ml of soln.
1020
g
m
in 1000 ml of soln.
Number ofr moles
=
2
⋅
05
M
×
1
l
i
t
=
2.
05
m
o
l
Mass of solute
=
n
×
M
⋅
w
t
=
2.
05
×
60
=
123
g
m
Mass of solvent
=
1020
−
123
=
897
g
m
Molality
=
123
60
×
1000
897
=
2.28
m
o
l
k
g
−
1
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