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Question

Density of a 2.05 M solution of acetic acid in water is 1.02 g/ml. The molality of the solution is :

A
1.14 mol kg1
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B
3.28 mol kg1
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C
2.28 mol kg1
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D
0.44 mol kg1
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Solution

The correct option is C 2.28 mol kg1
Suppose the volume of solution is 1000 ml.

1.02 gm of acetic acid in 1 ml of soln.

1020 gm in 1000 ml of soln.

Number ofr moles =205M×1 lit=2.05 mol

Mass of solute =n×Mwt=2.05×60=123 gm
Mass of solvent =1020123=897 gm
Molality =12360×1000897=2.28 mol kg1

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