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Question

Derive an expression for the magnetic dipole moment of a revolving electron.


Solution

The current in a loop due to a revolving electron $$=\dfrac{q}{T}$$ $$=\dfrac{q}{2\pi r/v}$$ $$=\dfrac{qv}{2\pi r}$$

Hence, magnetic moment due to the revolving charge $$=IA$$ $$=\dfrac{qv}{2\pi r}\pi r^2$$ $$=\dfrac{qvr}{2}$$

Physics

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