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Question

Derive the third equation of motion graphically.

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Solution

Consider the velocity-time graph of a body moving with uniform acceleration 'a'.

Distance travelled in time t, s=(OA+BC)×OC2
=(u+v)×t2
From the first equation of motion, t=(vu)a
Substituting we get, s=(v+u)×(vu)2a2as=v2u2

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