Question

Determine the current $I$ in the circuit and also determine the potential difference across battery $E_1$ and resistor $R_1$? [AII batteries are ideal]

Answer 1

Step 1:

Given data:

For the circuit shown in the figure:

Formula used:

$I=\frac{R}{V}$, where $I$ is the current, $R$ is the Resistor, $V$is the voltage

Step 2:

The given figure is modified as follows,

Start from point A and go on in a clockwise direction applying K.V.L.

$5I+3I+2I+4I+10+3I-5=0$

$I=-\frac{5}{17}\text{A}$ (1)

The positive sign shows that current I in the circuit is in an anticlockwise direction.

The positive sign shows that current I in the circuit is in an anticlockwise direction $\iota =-\frac{5}{17}A$

Step 3:

Calculation of the potential difference across battery $E_1$ and resistor $R_1=5\Omega$

$V=IR$

$$\begin{gathered} V=5\times \frac{5}{17} \\ =\frac{25}{17}V \end{gathered}$$

The current in the circuit is $\iota =-\frac{5}{17}A$ and the potential difference across battery $E_1$ and resistor $R_1$ is $\frac{25}{17}V$.