Question

Question 189

Determine the least number which when divided by 3,4 and 5, leaves remainder 2 in each case.

Answer 1

Firstly, we have to find the LCM of 3,4 and 5.

$\begin{array}{ccc}& 2& 3,4,5\\ & 2& ,3,2,5\\ & 3& ,3,1,5\\ & 5& ,1,1,5\\ & & 1,1,1\end{array}$

LCM of 3, 4 and 5 = 2 x 2 x 3 x 5 = 60

Now, required number = LCM of 3, 4 and 5 + Remainder = 60 + 2 = 62

Hence, the required number is 62.