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Question

Determine the molecular formula and calculate the percent composition of each element present in nicotine, which has a molecular weight of 162 g/mol and an empirical formula of C5H7N.

A
C10H14N2; 74.1% C, 8.6% H, 17.3% N
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B
C15H21N3; 84.1% C, 8.6% H, 17.3% N
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C
C10H14N2; 54.1% C, 3.6% H, 17.3% N
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D
C10H21N2; 84.1% C, 18.6% H, 17.3% N
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