Question

Determine the nature of the roots of the following equations from their discriminants.

$y^2+6y-2=0$

• A. real and equal
• B. real and unequal
• C. Complex
• D. Cannot be determined

Answer 1

The correct option is B real and unequal

Given equation is,

$y^2=6y-2=0$
We know,

$D=b^2-4ac$
$a=1,b=6,c=-2$

$D=(6{)}^2-4(1\left)\right(-2)$
$\therefore D=44$
Since, $D>0$ hence, the roots are real and unequal.