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Question

 Determine the ratio in which the line 3x+y9=0 divides the line segment joining the points (1, 3) and (2, 7).
[4 MARKS]
 


Solution

Formula: 1 Mark
Steps: 2 Marks
Answer: 1 Mark

Let the required ratio be k :1
Using section formula, we have 
x=1×1+2×kk+1=2k+1k+1
and y=1×3+7×kk+1=7k+3k+1



Point P (x, y) lies on the line 3x+y9=0, so
3(2k+1k+1)+(7k+3k+1)9=03(2k+1)+(7k+3)9(k+1)k+1=06k+3+7k+39k9=04k3=04k=3
So, k=34
Required ratio is 3 : 4
 

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