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12H2(g)H(g)  ΔHf=50 kcal/mol
PH3(g)P(g)+3H(g)ΔHdissociation=243 kcal/mol
P - P bond dissociation energy is x×10 kcal/mol. The value of x in nearest possible integer is


Solution

DHH=50×2kcal/molDPH=2433=81kcal/molXpXH=0.208Δ;Xelectronegativity,
Since P and H have half filled electronic configuration,
XP=XH,HenceΔ=0
Δ=DPH(DPP)(DHH)=0
D2PH=(DPP)(DHH)
DPP=D2PHDHH
=81×81100
=65.61 kcal/molDPP=6.5×10 kcal/molx=7

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