Question

# $$\dfrac{1}{3}x - \dfrac{1}{6}y = 4$$$$6x - ay = 8$$In the system of equations above, $$a$$ is a constant. If the system has no solution, what is the value of $$a$$

A
13
B
1
C
3
D
0

Solution

## The correct option is C $$3$$$$\dfrac{1}{3}x - \dfrac{1}{6}y = 4$$$$6x - ay = 8$$condition for no solution $$\dfrac{{{a_1}}}{{{a_2}}} = \dfrac{{{b_1}}}{{{b_2}}} \ne \dfrac{{{c_1}}}{{{c_2}}}$$$$\dfrac{\dfrac 13}{6} = \dfrac{{\dfrac{{ - 1}}{6}}}{{ - a}} \ne \dfrac{4}{8}$$$$6a = 6 \times 3$$$$a = 3$$Mathematics

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