$\frac{3}{7} + \frac{1}{4} \times \frac{16}{21} - \frac{1}{3}$

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Solution

$\frac{3}{7} + (\frac{1}{4} \times \frac{16}{21}) - \frac{1}{3}$
$= \frac{3}{7} + \frac{4}{21} - \frac{1}{3}$
$= \frac{9 + 4}{21} - \frac{1}{3} = \frac{13}{21} - \frac{1}{3} = \frac{13 - 7}{21} = \frac{6}{21} = \frac{2}{7}$

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