4x + 73 = 3x 24 + 12 4x + 73 = 3x 2 + 24 4x + 73 = 3x4 ⇒ 4 ( 4x + 7 ) = 3 ( 3x ) ⇒ 16x + 28 = 9x ⇒ 16x 9x = 28 ⇒ 7x = ...

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Byju's Answer

Standard X

Mathematics

Reversing the Terms

4x+73=3x-24+1...

Question

$\frac{4 x + 7}{3} = \frac{3 x - 2}{4} + \frac{1}{2}$

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Solution

$\frac{4 x + 7}{3} = \frac{3 x - 2}{4} + \frac{1}{2}$

$\frac{4 x + 7}{3} = \frac{3 x - 2 + 2}{4}$

$\frac{4 x + 7}{3} = \frac{3 x}{4}$

$\Rightarrow 4 (4 x + 7) = 3 (3 x)$
$\Rightarrow 16 x + 28 = 9 x$
$\Rightarrow 16 x - 9 x = - 28$
$\Rightarrow 7 x = - 28$
$\Rightarrow x = \frac{- 28}{7} = - 4$
Hence the correct answer is $- 4$ .

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\frac{1}{\sqrt{(3 x + 4)} - \sqrt{(3 x + 1)}} + \frac{8 x + 13}{\sqrt{(4 x + 7)}} + (7 x - 2) \sqrt{3 x + 2} .

\int_{0}^{1} \frac{(3 x^{4} + 4 x^{3} + 3 x^{2})}{(4 x^{3} + 3 x^{2} + 2 x + 1)^{2}} d x

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Q. What must be subtracted from

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to get

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Answer:

x^{4} - 3 x^{3} + 5 x^{2} - 5 x + 6

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve:

\frac{3 x + 5}{4 x + 2} = \frac{3 x + 4}{4 x + 7}

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4x+73=3x−24+12

4x+73=3x−24+124x+73=3x−2+244x+73=3x4⇒4(4x+7)=3(3x)⇒16x+28=9x⇒16x−9x=−28⇒7x=−28⇒x=−287=−4Hence the correct answer is −4.

$\frac{4 x + 7}{3} = \frac{3 x - 2}{4} + \frac{1}{2}$