Question

Diagram of the adjacent picture frame has outer dimensions = 24 cm $\times$ 28 cm and inner dimensions 16 cm $\times$ 20 cm. Find the area of Section BEFC of the frame, if the width of each section is same.

Answer 1

Given that, the width of each Section is same.
Therefore, IB = BJ= CK =CL = DM = DN = AO =AP
IL= IB +BC + CL
28= IB + 20 +CL
IB+CL =28cm - 20 cm = 8cm
IB =CL = 4cm
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Hence, IB =BJ=CK=CL=DM=DN=AO=AP=4cm
Area of Section BEFC =Area of section DGHA
=$\frac{1}{2}(20+28)\left(4\right)]c{m}^2=96c{m}^2$
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