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Question

Differentiate sinx+excosx+ex with respect to x.

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Solution

ddx(sinx+logxcosx+ex)
=(cosx+ex)ddx(sinx+ex)(sinx+ex)ddx(cosx+ex)(cosx+ex)2
=(cosx+ex)(cosx+ex)(sinx+ex)(sinx+ex)(cosx+ex)2
=(cosx+ex)2(sin2x+e2x)(cosx+ex)2
=cos2x+2excosx+e2x+sin2xe2x(cosx+ex)2
=2excosx+1(cosx+ex)2

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