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Question

Differentiate log|tanx|+12tan2x+C.

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Solution

ddx(log|tanx|+12tan2x+c)
=ddx(log|+tanx|)+ddx(12tan2x)+ddx(c)
=1|tanx|.ddx(|tanx|+12.2tanxddx(tanx)+0
=sec2xtanx+tanx.sec2x

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