Question

Differentiate the following function with respect to x.

$(2x^2-3)\sin x$.

• A. $4x\sin x-(2x^2-3)\cos x$
• B. $4x\sin x+(2x^2+3)\cos x$
• C. $4x\sin x+(2x^2-3)\cos x$
• D. None of the above

Answer 1

The correct option is C

$4x\sin x+(2x^2-3)\cos x$

Given expression

$(2x^2-3)\sin x$

$\frac{d}{dx}\left(\right(2x^2-3\left)\sin x\right)$

$\frac{d}{dx}(2x^2-3)\sin x+2x^2-3\frac{d}{dx}\left(\sin x\right)$

$⟹4x\sin x+(2x^2-3)\cos x$