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Question

Differentiate the following questions w.r.t. x.

cos(log x+ex).


Solution

Ley y = cos(log x+ex).

Differentiate both sides w.r.t. x, we get

   dydx=ddx{cos(log x+ex)}   dydx=sin(log x+ex)ddx(log x+ex)   (Using chain rule)   dydx=sin(log x+ex)(1x+ex)dydx=(xex+1)sin(log x+ex)x

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