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Question

Differentiate the following questions w.r.t. x.

cos(log x+ex).

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Solution

Ley y = cos(log x+ex).

Differentiate both sides w.r.t. x, we get

dydx=ddx{cos(log x+ex)} dydx=sin(log x+ex)ddx(log x+ex) (Using chain rule) dydx=sin(log x+ex)(1x+ex)dydx=(xex+1)sin(log x+ex)x


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