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Question

Differentiate the function with respect to x:
(sinx)x+sin1x

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Solution

y=(sin x)x+sin1x
let t=(sin x)x
log t=x log(sinx)
Differentiating both sides wrt x
1tdtdx=1.log(sinx)+x cosxsinx
dtdx=(sinx)x(xcotx+logsinx)
y=t+sin1x
Differentiating both sides wrt x
dydx=dtdx+d(sin1x)dx
dydx=12x(1x)+(sinx)x(xcotx+logsinx)$

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