Question

Differentiate with respect to $x$:
$({\sin }^{-1}{x}^4{)}^4$

Answer 1

=$\frac{d}{dx}\left(\right(si{n}^{-1}{x}^4{)}^4\left)\right)$

$=4(si{n}^{-1}{x}^4{)}^3\times \frac{d}{dx}(si{n}^{-1}{x}^4)$

$=\frac{4(si{n}^{-1}{x}^4{)}^3}{\sqrt{1-x^8}}\times \frac{d}{dx}\left(x^4\right)$

$=\frac{16x^3(si{n}^{-1}{x}^4{)}^3}{\sqrt{1-x^8}}$