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Question

Dihybrid cross is made between RRYY (yellow round seed) and yyrr (wrinkled green seed) of Pea. $$F_2$$ ratio amongst round yellow, round green, wrinkled yellow and wrinkled green would be


A
9 : 3 : 3 : 1
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B
15 : 1 : 0 : 0
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C
9 : 3 : 4 : 0
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D
4 : 4 : 4 : 4
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Solution

The correct option is B 9 : 3 : 3 : 1

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

So, the correct option is ‘9:3:3:1’. 
1131167_688174_ans_00dcaa79dcfd48ee9689b9ee3c950881.jpg

Biology

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